lim x tends to 1 {1/( x2+x-2) - x/ (x3-1)} is evaluated to be a)1/9 b)9 c)-1/9 d) none of these Share with your friends Share 5 Anuradha Sharma answered this limx→1 1x2+x-2-xx3-1Now 1x2+x-2-xx3-1= 1x2+2x-x-2-xx-1x2+x+1 =1x+2x-1-xx-1x2+x+1 =1x-11x+2-xx2+x+1 =1x-1x2+x+1-x2-2xx+2x2+x+1 =1x-11-xx+2x2+x+1=-1x+2x2+x+1Now putting this we get, limx→1 1x2+x-2-xx3-1=limx→1-1x+2x2+x+1=-11+21+1+1=-19 6 View Full Answer Ritesh Yadav answered this 1/(x2+x-2)=1/{(x-1)(x+2)}1/(x-1) {1/(x+2) - x/(x2+1+x)}1/(x-1){(1-x) / (x+2)(x2+x+1)}-1 /(x+2)(x2+x+1))putting limits-1/9 3