lim x tends to 0 1-cos4x /x2 =r lim x tends to 0r 1-1+2sin2(2x)/x2 [since cos2x=1-sin2 x]
=> lim x tends to 0 2sin2(2x)/x2
Multiplying 4 in numerator and denominator,
=>lim x tends to 0r 8sin2(2x)/(2x)2
=>8
Therefore , lim x tends to 0 1-cos4x/x2 = b