Limit (x --> 0) (tan 3x - 2x)/(3x - sin square x)

limx0tan3x-2x3x-sin2xIt is 00 form so using L'hospital rule we get, limx0ddxtan3x-2xddx3x-sin2x=limx03sec23x-23-2sinxcosx=3-23-0=13

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