limit x tends to 0, [cube root (8+x)-2]/x Share with your friends Share 0 Varun.Rawat answered this limx→08+x3 - 2x=limx→0138+x-2/3 - 01 Using L' Hospital's rule=13limx→0 8+x-2/3=138-2/3=1323-2/3=13 × 14=112 1 View Full Answer
