limit(x tends to 0)(x/tan-1(2x))

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Please find below the solution to the asked query:

We have:L=limx0 xtan-12x=12limx0 2xtan-12xBy standard form we have:limxa fxtan-1fx=1, where limxa fx=0Hence limx0 2xtan-12x=1L=12×1=12limx0 xtan-12x=12

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