limxtend to 3 x^3-27/root x^2+7-4 Share with your friends Share 1 Ajanta Trivedi answered this the given limit is limx→3x3-27x2+7-4 i.e. 00 formso we can apply L'Hospital rule:limx→3ddx(x3-27)ddx(x2+7-4)=limx→33x212x2+7.2x=limx→3[3.x2+7]=3*32+7=3*9+7=3*16=3*4=12 hope this helps you 3 View Full Answer