linear equation by substitution method

s-t=3 ,s/3+t/2=6

GIVEN :-  Equation 1) s - t =3

  2) ( s / 3 ) + ( t / 2 )= 6

Solution:-

As  s - t = 3

  = s = t +3

Substituting the value in Equation 2 :- ( s / 3 ) + ( t / 2 ) = 6

  = [ (t + 3) / 3 ] + ( t / 2 ) = 6

  = ( t / 3 ) + (3 / 3) + ( t / 2 ) = 6

  = ( t / 3 ) + ( t / 2 ) + 1 = 6

  = (3t + 2t) / 6 = 6 - 1

  = 5t / 6 = 5

  = 5t = 30

  = t = 30 / 5 = 6

Therefore, t = 6

As by Equation 1 :-  s - t = 3

  = s - 6 = 3

  = s = 3 + 6 = 9

Therefore s = 9  and  t = 6.