log(4/3*3.14*0.87*0.87)=?

log(43×3.14×0.87×0.87)=log(43×3.14×(0.87)2)=log(43)+log(3.14)+log(0.87)2 [Using log abc =log a +log b +log c] =log4-log3+log3.14+2log(0.87) [ using logab=loga-logb and logab=bloga]Now,we require the different log value,which can be obtained by logarithmic table.log(43×3.14×0.87×0.87)=0.60-0.47+0.49+2(-0.060)=0.50

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