log4(2log3( 1 + log2( 1 + 3log3 x))) = 1/2. Find x.
Given,
log4(2log3( 1 + log2( 1 + 3log3 x))) = 1/2.
now we know that
,
(2log3( 1 + log2( 1 + 3log3 x))) = 41/2 =2
2log3( 1 + log2( 1 + 3log3 x)) = 2
log3( 1 + log2( 1 + 3log3 x)) = 1
1 + log2( 1 + 3log3 x) = 31
log2( 1 + 3log3 x) = 3-1= 2
1 + 3log3 x = 22
3log3 x = 4-1 = 3
log3 x =1 or x = 31 =3
x = 3
Answer
log4(2log3( 1 + log2( 1 + 3log3 x))) = 1/2.
now we know that
,
(2log3( 1 + log2( 1 + 3log3 x))) = 41/2 =2
2log3( 1 + log2( 1 + 3log3 x)) = 2
log3( 1 + log2( 1 + 3log3 x)) = 1
1 + log2( 1 + 3log3 x) = 31
log2( 1 + 3log3 x) = 3-1= 2
1 + 3log3 x = 22
3log3 x = 4-1 = 3
log3 x =1 or x = 31 =3
x = 3
Answer