log4(2log3( 1 + log2( 1 + 3log3 x))) = 1/2. Find x.

Given, 
log4(2log3( 1 + log2( 1 + 3log3 x))) = 1/2. 
now we know that
If logmn=k then n = mk using this property we can easily solve the problem, log4(2log3(1+log2(1+3log3x))) = 1/2


(2log3( 1 + log2( 1 + 3log3 x))) = 41/2 =2
2log3( 1 + log2( 1 + 3log3 x)) = 2
log3( 1 + log2( 1 + 3log3 x)) = 1

 1 + log2( 1 + 3log3 x) = 31
 
log2( 1 + 3log3 x) = 3-1= 2 
 1 + 
3log3 x = 22
 
3log3 x  = 4-1 = 3
log3 x  =1  or x = 3=3
x = 3
Answer

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