(loga)/2 = (logb)/3 = (logc)/7 then a^2 is This question has not been answered yet! Don't worry! You can check out similar questions with solutions below Evaluate. loga baseb. logb basec. logc baseathe value of x satisfying loga(1+ logb [ 1 + logc (1+ logpx) ... ... solve this fast loga _ logb _ logc then prove tnataa bb ... ... the equation loga(1+logb{1+logc(1+logpx)}) = 0 and ... ... that loga n loga n — logb n logc n ¯ logb n — logc ...
