(m/n)x^2 + n/m = 1 - 2x

m/n x2+n/m =1-2x

mn*m/n x2+mn*n/m =mn*1-mn*2x

m2 x2+n= m n-2xmn

m2 x2+2 x m n+n2-m n =0

m2 x2+2 m n x+n(n-m) =0

therfore, x =[-2 m n +- {(-2 m n )2- 4 mn (n-m)}1/2] / 2m2 [using,fomula]

=[-2 m n+-{4 mn2-4 mn2+4 mn}1/2] / 2m[power of 1/2 means rootover]

=[-2mn+{-4m3n}1/2] / 2m2

={-2mn+-2m*(mn)1/2} / 2m2

=-n+-(mn)1/2/ m [by cancelling 2m]

=-n/m+-(n/m)1/2

 

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  • 9

m/n x2+n/m =1-2x

mn*m/n x2+mn*n/m =mn*1-mn*2x

m2 x2+n= m n-2xmn

m2 x2+2 x m n+n2-m n =0

m2 x2+2 m n x+n(n-m) =0

therfore, x =[-2 m n +- {(-2 m n )2- 4 mn (n-m)}1/2] / 2m2 [using,fomula]

=[-2 m n+-{4 mn2-4 mn2+4 mn}1/2] / 2m[power of 1/2 means rootover]

=[-2mn+{-4m3n}1/2] / 2m2

={-2mn+-2m*(mn)1/2} / 2m2

=-n+-(mn)1/2/ m [by cancelling 2m]

=-n/m+-(n/m)1/2

  • 2
Is it possible to do this with middle term splitting? Not with quadratic formula.
  • -8
Hello! Here is the easiest answer to this question.

  • 32
its so easy
  • -10
What are you looking for?