Magnetic field at a point (x, y, z) is given by B → = B 0 y x 2 + y 2 1 2 i ^ - B 0 x x 2 + y 2 1 2 j ^ . Find current enclosed in the loop x 2 + y 2 = r 2. (1) B 0 r µ 0 (2) 2 B 0 r µ 0 (3) 2 π B 0 r µ 0 (4) B 0 r 2 µ 0 Share with your friends Share 24 Manoj Singh answered this Dear Student, Use ampere circuital law ∮B.dl = μ0Ienclosed ..(1)Use stokes theorem∮B.dl = ∬∇×B.ds .....(2)First we calculate ∇×B. I can not write indermidiate steps.∇×B = k^(-B0r+B0x2r3)-(B0r-B0y2r3) =k^(2B0r+B0r3(x2+y2)) = -B0r k^Applying in 1 equation∮B.dl = ∬-B0r k^.ds=B0r ∬ds = B0rπr2 = B0πrFrom equation 1Ienclosed = B0πrμ0 -72 View Full Answer Prakhar Kushwah answered this Never mind -29