Magnetic field at a point (x, y, z) is given by  B = B 0 y x 2 + y 2 1 2 i ^ - B 0 x x 2 + y 2 1 2 j ^ . Find  current enclosed in the loop
x 2 + y 2 = r 2.

(1)  B 0   r µ 0                        (2)  2 B 0   r µ 0                       (3)  2 π   B 0   r µ 0                 (4)  B 0   r 2   µ 0

Dear Student,

Use ampere circuital law
B.dl = μ0Ienclosed    ..(1)Use stokes theoremB.dl = ×B.ds    .....(2)First we calculate ×B.    I can not write indermidiate steps.×B = k^(-B0r+B0x2r3)-(B0r-B0y2r3) =k^(2B0r+B0r3(x2+y2))   = -B0r k^Applying in 1 equationB.dl = -B0r k^.ds=B0r ds = B0rπr2 = B0πrFrom equation 1Ienclosed =  B0πrμ0

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Never mind
 
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