Magnetic flux through a circuit of resistance 20 ohm is changed from 20-40Wb in 5 ms. charge passed through the circuit during this time? ?? Share with your friends Share 2 Govind answered this Given,Resistance of the circuit, R=20 ΩTime, t=5 msEmfe is given bye=dϕdt⇒e=40-205×10-3=4×103 VCurrent passing through the circuitI is given byI=eR=4×10320⇒I= 200 AChargeq will beq=Idt=200×5×10-3=1C 61 View Full Answer Stuti answered this EMF = CHANGE IN FLUX / TIME TAKEN = 40-20 / 300 = 20 / 300 = 2 / 30. CURRENT = EMF / RESISTANCE = 2/30 / 20 = 1 / 300 CHARGE = CURRENT * TIME = 1/300 * 300 = 1 COULOMB. 5
