make a quadrilateral PLAN where:
angle P=90 degree
angle A=110 degree
here we need to make a quadrilateral PLAN, such that
PL = 4 cm, LA = 6.5 cm, ∠P = 90 ; ∠N = 85 ; ∠A = 110
since the sum of interior angles of a quadrilateral is 360 deg.
∠L = 360-(∠P+∠N+∠A)
= 360 - (90+85+110)
= 360 - (285)
= 75 deg.
steps of constructions :
1. draw a line segment PL = 4 cm.
2. at P , draw an angle 90 deg and at L draw an angle of 75 deg.
3. from L , draw an arc of length 6.5 cm to cut the angle line at A.
4. at A , draw an angle of 110 deg.
let it intersect at N.
thus PLAN is the required quadrilateral.