make a quadrilateral PLAN where:

PL=4cm

LA=6.5cm

angle P=90 degree

angle A=110 degree

angleN=85 degree

here we need to make a quadrilateral PLAN, such that

PL = 4 cm, LA = 6.5 cm, ∠P = 90 ; ∠N = 85 ; ∠A = 110

since the sum of interior angles of a quadrilateral is 360 deg.

∠L = 360-(∠P+∠N+∠A)

= 360 - (90+85+110)

= 360 - (285)

= 75 deg.

steps of constructions :

1. draw a line segment PL = 4 cm.

2. at P , draw an angle 90 deg and at L draw an angle of 75 deg.

3. from L , draw an arc of length 6.5 cm to cut the angle line at A.

4. at A , draw an angle of 110 deg.

let it intersect at N.

thus PLAN is the required quadrilateral.

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