mass of 2.4088 into 10 raise to power 26 number of Helium atom is

Dear Student,

Given-
Number of atoms of Helium = 2.4088×1026 atoms
Molar mass of Helium (mHe) = 4 g/mol
Avogadro Number (NA) = 6.022×1023 atoms

We know that,

Number of Moles (nHe) = Number of atomsAvogadro Number
                              nHe = 2.4088×10266.022×1023
                              nHe = 0.4×103 or 4.0×102 moles
Now,

Number of moles (nHe) = Mass of Helium (wHe)Molar Mass of Helium (mHe)
Or
                              wHe = nHe × mHe
                              wHe = (4×102)×4
                              wHe = 16×102 grams

Regards

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