Maths q.2

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1.Draw a line PQ.

Take any point L on this line.

Construct perpendicular AL on PQ.

Cut a line segment AD from D equal to 4cm.

Make angles equal to 30° at A on both sides of AD, say ∠CAD and ∠BAD where B and C lie on XY.

Then, ABC is the required triangle.

 

Justification:

Since ∠A = 30° + 30° = 60° and AL ⊥ BC,

Therefore, ∆ABC is an equilateral triangle with altitude AL = 4 cm.

  • -1
Draw a line bc of 6 cm.
Construct its perpendicular bisector or bisector.
The point made on the line-name it as D.
Make a 4 cm da line from that point.
Join ac &bc
Done!
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