MCQ 4
6. 
A circular hole of radius $\frac{\mathrm{R}}{4}$ is made in a 
thin uniform disc having mass M and 
radius R, as shown in figure. The moment 
of inertia of the remaining portion of the 
disc about an axis passing through the 
point O and perpendicular to the plane of 
the disc is : 

$$\begin{gathered} \left(1\right) \frac{219 {\mathrm{MR}}^2}{256} \\ \left(2\right)\frac{237 {\mathrm{MR}}^2}{512} \\ \left(3\right) \frac{19 {\mathrm{MR}}^2}{512} \\ \left(4\right) \frac{197 {\mathrm{MR}}^2}{256} \end{gathered}$$