mean =17number= 10variance =33out of these ten value one is 27 which was found to be innaccurateand thus weeded out .what is the resulting mean and standard deviation Share with your friends Share 1 Diksha Verma answered this Given: meanx¯ =17 variance =33 number=10, out of these ten value one is 27.x¯=x1+x2+x3+x4+x5+x6+x7+x8+x9+271017=x1+x2+x3+x4+x5+x6+x7+x8+x9+2710170=x1+x2+x3+x4+x5+x6+x7+x8+x9+27170-27=x1+x2+x3+x4+x5+x6+x7+x8+x9x1+x2+x3+x4+x5+x6+x7+x8+x9=143Let x¯' be the mean of remaining 9 values, then we have, x¯'=1439=15.88≃16 AnsVariance=x12+x22+x32+x42+x52+x62+x72+x82+x92+x10210-x¯233=x12+x22+x32+x42+x52+x62+x72+x82+x92+(27)210-17233=x12+x22+x32+x42+x52+x62+x72+x82+x92+72910-289(33+289)×10=x12+x22+x32+x42+x52+x62+x72+x82+x92+7293220=x12+x22+x32+x42+x52+x62+x72+x82+x92+7293220-729=x12+x22+x32+x42+x52+x62+x72+x82+x92x12+x22+x32+x42+x52+x62+x72+x82+x92= 2491Let∑x1' be the sum of the square of 9 values, thenσ2=∑x1' 9-x'¯2σ2=24919-(16)2σ2=276.7-256σ2=20.7σ=20.7Standard deviation (σ)≃4.55 Ans 0 View Full Answer
