MEENA WENT OUT FOR SHOPPING.SHE HAD IN HER HADBAG APPROXIMATELY RS15 IN ONE RUPEE NOTES AND 20p COINS WHEN SHE RETURNED SHE HAD AS MANY ONE RUPEE NOTES AS SHE ORIGINALLY HAD AS MANY 20p.coins as she orinally had one rupee notes .she actually came back with 1/3 of what she had started with. how much did she spend and how much did she have when she started?

Suppose Meena had x one rupee notes and y 20 paise coins.
So going shopping she had 100x+20y
And according to the question, when she returned she had 100y+20x paise.
And when she returned,she actually came back with 1/3 of what she had started with. So we have;
100y+20x = 13100x+20y3100y+20x = 100x+20y 

Simplifying we have x = 7 if y = 1.
Assuming this Meena had 7.20 rupees when she set out for shopping. This is wrong because Meena actually had about 15 rupees.
Now putting y = 2. Then x = 14.
The original sum was 14.40 rupees, which accords with the condition of the problem.
Assuming y = 3 then the sum will be too big i.e. 21.60 rupees.
Therefore the only suitable answer is 14.40 rupees.
After shopping Meena had 2 one rupee notes and 14 twenty Paise coins.
This is actually 1/3rd of the original sum 13×14.40 = Rs.4.80
Therefore she spent Rs.4.80
And so her savings = Rs.14.40 - Rs.4.80 = Rs.9.60

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