MeritNation, Before some time, one of the Meritnation experts, I.E Brijendra pal sir, had answered one of my queries. But, the answer to the same was having some error, so I want him to recheck the following again. I have highlighted the error part in red colour. MeritNation, Before some time, one of the Meritnation experts, I.E Brijendra pal sir, had answered one of my queries. But, the answer to the same was having some error, so I want him to recheck the following again. I have highlighted the error part in red colour. EXPERT ANSWER 8riiendra Pal , Meritnation expert added an answer 15 minutes ago 1 1 We know that a3 + b3 x and b = 1 putting a x3 + 13 0 from equation 1 so x3 —1 Now x99 + = (x3)33 + 33 = (—1)33 1 1 This conversation is already closed by Expert —2 Was this answer helpful? @ Share with your friends Share 0 Brijendra Pal answered this Dear Santanu, We are sorry for the earlier answer, Please find the correct answer, x+1x= -1x2+1x= -1x2+1= -x x2+x+1=0 ....1We know that a3-b3= a-ba2+ab+b2putting a = x and b = 1 x3-13= x-1x2+x+1x3-1=x-1×0 = 0 from equation 1 so x3=1Now x99+1x99=x333+1x333=133+1133= 1+1= 2 1 View Full Answer
