min z = x+2y  subject to 
x+2y ​≥  50 
2x-y ​​, ≤ 0
2x+y, ≤ 100 &
​x,y ≥  0

Dear student


Min z=x+2y subject tox+2y502x-y02x+y100x,y0Taking above inequalities as equationsx+2y=502x-y=02x+y=100
Please recheck your constriant 2x-y0 because of which we are not able to get thecorner points
Regards

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