min z = x+2y subject to x+2y ≥ 50 2x-y , ≤ 0 2x+y, ≤ 100 & x,y ≥ 0 Share with your friends Share 1 Neha Sethi answered this Dear student Min z=x+2y subject tox+2y≥502x-y≤02x+y≤100x,y≥0Taking above inequalities as equationsx+2y=502x-y=02x+y=100 Please recheck your constriant 2x-y≤0 because of which we are not able to get thecorner points Regards 0 View Full Answer