mod of x^2 - 5x +4 / x^2 - 4 is less than or equal to 1 solve the inequality. Share with your friends Share 5 Ishwarmani answered this Dear student, Please find below the solution of the asked query: We have,x2-5x+4x2-4≤1⇒0≤x2-5x+4x2-4≤1⇒0≤x2-5x+4x2-4≤1 or -1≤x2-5x+4x2-4≤0⇒x2-5x+4x2-4≥0 and x2-5x+4x2-4≤1 or x2-5x+4x2-4≤0 and x2-5x+4x2-4≥-1⇒x2-5x+4x2-4≥0 and x2-5x+4x2-4-1≤0 or x2-5x+4x2-4≤0 and x2-5x+4x2-4+1≥0⇒x2-5x+4x2-4≥0 and x2-5x+4-x2+4x2-4≤0 or x2-5x+4x2-4≤0 and x2-5x+4+x2-4x2-4≥0⇒x2-5x+4x2-4≥0 and -5x+8x2-4≤0 or x2-5x+4x2-4≤0 and 2x2-5xx2-4≥0⇒x-1x-4x-2x+2≥0 and 5x-8x-2x+2≥0 or x-1x-4x-2x+2≤0 and x2x-5x-2x+2≥0⇒x∈-∞, -2∪[1, 2)∪[4, ∞) and x∈(-2, 85]∪2, ∞ or x∈(-2, 1]∪(2, 4] and x∈-∞, -2∪[0, 2)∪[52, ∞)⇒x∈1, 85∪[4, ∞) or x∈0, 1∪52, 4∴ x∈0, 85∪[52, ∞) Regards 4 View Full Answer
