Mole fraction of solvent in aqueous solution of naoh having molality of 3 is ?

Dear Student,

The computation are as expressed below,

3 m of solution denotes 3 moles of solute in 1000 gm of solvent (water)No. of moles of NaOH = 3No. of moles of water (solvent) = massmolar mass=100018 =55.55 molesMole fraction = moles of solventmoles of solute +moles of solvent                          = 55.553+55.55=55.5558.55=0.948760.95
Regards.

  • 6
What are you looking for?