Mole fraction of solvent in aqueous solution of naoh having molality of 3 is ? Share with your friends Share 1 Yasodharan answered this Dear Student, The computation are as expressed below, 3 m of solution denotes 3 moles of solute in 1000 gm of solvent (water)No. of moles of NaOH = 3No. of moles of water (solvent) = massmolar mass=100018 =55.55 molesMole fraction = moles of solventmoles of solute +moles of solvent = 55.553+55.55=55.5558.55=0.94876≈0.95 Regards. 5 View Full Answer