# Moment of inertia of rod about an axis perpendicular to its and passing through its centre is equal to ML^2/2 . Find moment of inertia of rod about an axis perpendicular to its passing through its 1 end.

$useparallelaxistheorem.\phantom{\rule{0ex}{0ex}}MI=\frac{M{L}^{2}}{2}+M{\left(\frac{L}{2}\right)}^{2}=\frac{M{L}^{2}}{2}+\frac{M{L}^{2}}{4}=\frac{3M{L}^{2}}{4}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}REgards$

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