mon difference of arithmetic is 1 and product of first and third terms is 143,find first three terms - Maths - Second Degree Equations

Question

mon difference of arithmetic is 1 and product of first and third
terms is 143,find first three terms

Shruti Tyagi · Accepted Answer

Dear student,
We have,common difference, d = 1 let a be the first term Acc
 to question,a×third term= 143 ⇒a×[a+(3−1)d]= 143        --[using an=a+n-1d]⇒a×[a+2]= 143 ⇒a2+2a= 143 ⇒a2+2a-143=0⇒a2+13a-11a-143=0 ⇒aa+13-11a+13=0 ⇒a+13a-11=0 ⇒a=-13 and a=11when a=11 second term a2=a+d=11+1=12third term a3=a+2d=11+2=13when a=-13second term a2=-13+d=-13+1=-12third term a3=a+2d=-13+2=-11
Regards