Mr.Kapur withdrew rs.25000 from an ATM.If he received 150 notes in denominations of rs.500 and rs.100,find the no. of notes of each denomination?although i know how to do it, but it is a 2 variable method...can u suggest a 1 variable method?ans-25,125thanx

Suppose the number of Rs.500 notes be x.
Total number of notes = 150
Then, number of Rs.100 notes = $\left(150-x\right)$
Amount of 150 notes = $500x+100\left(150-x\right)$
Total amount withdrew from an ATM = Rs.25000
So we have;
$500x+100\left(150-x\right)=25000\phantom{\rule{0ex}{0ex}}⇒500x+15000-100x=25000\phantom{\rule{0ex}{0ex}}⇒400x=25000-15000\phantom{\rule{0ex}{0ex}}⇒x=\frac{10000}{400}=25$
Therefore number of Rs.500 notes = 25 and number of Rs.100 notes = $150-25=125$

• 7

let the number 500 rs notes be x

and number of 100rs notes be (150-x)

according to the condition

25000 = x(500) + (150 - x)(100)

25000 = 500x + 15000 - 100x

25000 = 500x - 100x +15000

25000 -15000 = 400x

10000 = 400x

x=10000/400

x=25

number of 500 rs notes = x=25 notes

number of 100rs notes = 150 - x=150-25 = 125 notes

• 3
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