Mrs jain is 5 times as old as her daughter . Six years later she will be three times as old as her daughter . Find the present age of mre jain

Let the present age of daughter = x yrsThen present age of Mrs. Jain = 5x yrs6 YEARS LATER :Daughter's age =x + 6 yrsMrs . Jain's age = 5x+6 yrsNow, according to question :5x + 6 = 3x + 65x + 6 = 3x + 185x - 3x = 18 - 62x = 12x = 6So, present age of daughter = 6 yrsPresent age of Mrs. Jain = 5×6 = 30 yrs

  • 5
let mrs jain's age be x years
so her daughter's age will be x/5 years

after six years mrs jain's age will be x+6 years
so at that time her daughter's age will be x/5 +6  years

so the equation that will be formed is :-
x+6 = 3x/5 + 6
x = 3x/5
2x = 3*5
2x = 15
x = 15/2
x = 7.5
  • 1
X=7.5
  • 0
Mrs Jain's present age is 30 yrs
  • 0
What are you looking for?