if p and q are the zeroes of quadratic equation Ax^2 +Bx + C = 0
p+q = -B/A and pq = C/a
GIven p = 2 and q = -3
GIven quadratic equation is x^2 + (a+1)x +b =0
thus mapping it to Ax^2 +Bx + C = 0
A = 1, B = a+1 C = b
and if roots are p and q given to be 2 and -3
p + q = -B/A = -(a+1)/1 = -1( 2 + (-3) ) = 1
pq = C/A = b = 2*(-3) = -6
thus a+1 = 1 and b = -6
a = 0
Option D
proof roots are 2 and -3
thus equation is (x - 2)(x +3) = x^2 +x -6
a+1 = 1 and b = -6
