NCERT Textbook Class 8 Maths Chapter 11 Mensuration Pg. no. 170 Try These Question (a) and (b)

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Try these of ch 11 pg no 175 and176
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Heme
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Perimeter of triangle
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answer plez

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I don't know what to do

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Try these chapter 11 page 170
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Match the following with their respective areas in the box
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Answer the question

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The length of a rectangular field increased by 50 percent and it's breadth is decreased by 50 percent to form a new rectangular field.find the percentage change in the area of the field
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Mathematics textbook for class 8 chapter 11 exercise 11.1
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Hi plz tell the solution of try these of chapter 11

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Tha curved surface area of a clinder is 1320 cm and it's volume is 2640 cm find its height
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match the respected with same area figure.
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Perimeter of parallelogram= sum of all sides =14+7+14+7= 42 cm Perimeters of other figures are given in the below image

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Match the following figures with their respective areas in the box

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Please help me in doing this question

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Try these
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The length of a rectangular field increased by 50 percent and its breadth is decreased by 50 percent to form a new rectangular field.find the percentage change in the area of the field
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What is the answer

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Try these

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This is a helpful answer

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Jss7jc7f
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Answer these and tell me in aformat

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perimeter of a parallelogram is 2*(side+base)
                                                =2*(7+14)   
                                                 =49
perimeter of a triangle=a+b+c
                                    =9+14+11
                                    =34
perimeter of a rectangle=2*(l+b)
                                      =2(14+7)
                                       =42
perimeter of a square=s*s 
                                   =7*7
                                   =49 
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Please find this answer

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To find area of triangle

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Match the er following figures with their respective areas in the box
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Match the following figures with their respective areas in the box

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Fdhc. V
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400000
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my question is mathematics and first our room is 15 metre long and 10 metre broad and area of its four walls is 750 metre square find the height of the room
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Dear friend... please specify the question so that I can help you. Hope you can understand...
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chapter 4 area of triangles and quadrilaterals question number 10
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the base of an isosceles triangle measure 80 cm and its area is 360 CM square find the perimeter of the triangle
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So basically the meaning of pie is "circumference of circle" and the value of Pie : it's on fraction and decimal form also.
Fraction: 22/7 and Decimal : 3.104 and so on.
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perimeter of a parallelogram is 2*(side+base)
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? =2*(7+14)? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?=49
perimeter of a triangle=a+b+c
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? =9+14+11
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? =34
perimeter of a rectangle=2*(l+b)
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? =2(14+7)
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?=42
perimeter of a square=s*s?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?=7*7
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?=49?
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try these a and b page 170
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2(lb+bh+hl)
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Answer please

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