Need help with this one

Need help with this one 16 Show that 0) + tan(600 + 0) - 8)

Dear Student,

\frac{\cos^{2} (45 ° + θ) + \cos^{2} (45 ° - θ)}{\tan (60 ° + θ) \tan (30 ° - θ)} = 1 = \frac{\sin^{2} [90 ° - (45 ° + θ)] + \cos^{2} (45 ° - θ)}{\cot [90 ° - (60 ° + θ)] \tan (30 ° - θ)} [U s i n g c o s θ = s i n (90 - θ), t a n θ = c o t (90 - θ)] = \frac{\sin^{2} (45 ° - θ) + \cos^{2} (45 ° - θ)}{\cot (30 ° - θ) \tan (30 ° - θ)} [U s i n g s i n^{2} θ + c o s^{2} θ = 1 a n d c o t θ t a n θ = 1] = \frac{1}{1} = 1 = RHS Hence Proved

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