[NiCl4]2- .
explain the bonding in coordination compounds ?
show the hybridisation in [NiCl4]2- .
and explain each nad every step in hybridisation
Dear student!
The compound [NiCl4]2- , has sp3 hybridization which is determined as:
At step 1: we find the metal cation and as, x + (-4) = -2 or x = +2, So, metal ion is Ni+2 ion , whose configuration is 3d8
Step2 : Further, Cl, forms high spin complex , it could not pair up the unpaired electrons of 3d-orbital and so the four electrons pair donated by Cl-atoms are arranged in 4 sp3 hybridized orbitals.
The detailed mechanism is given as below:
