Nine identical books each of mass 500 g are placed one above the other.find the maximum force required to take out the fifth book of the coefficient of feiction becimes contact surfaces of the books is 0.2s

Dear Student ,
Here in this case the co efficient of friction is 0.2 and the mass of total 5 book is = 5 x 500 = 2500 gm = 2.5 kg
Therefore the maximum force required to take out the fifth book is ,
Fmax=μmg=0·2×2·5×10=5 N
Regards

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