no force acts on the charge fired through a magnetic field,when the angle between its velocity and magnetic field is:-

a) pie

b) pie/2

c) 3pie/2

d) pie/4

Force $q,{bf v}times{bf B}$= q v B sin ( Q) acting on the particle only depends on the component of the particle's velocity which is perpendicular to the direction of magnetic field (the cross product of two parallel vectors is always zero  

because the angle 
$theta$ they subtend is zero). Or we can say that the angle is 180 degrees or pie . so the answer will be pie 

  • -2
What are you looking for?