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( NO LINKS ). Solve 17(a).
Q.17. (a) Find the perimeter and area of the figure (i) given below in which all corners are right angles.




Perimeter of ABCDEF = AB+BC+CD+EF+FA=2 + 4 + 4 + 1.5 + 6 + 5.5=23 m

Extend BC to G that intersects EF at G.Now, area of ABGF = AB×BG = 2 ×5.5 = 11 m2Now, area of CDEG = CD×DE = 4 × 1.5 = 6 m2So, area of the given figure =area of ABGF +  area of CDEG=11 + 6 = 17 m2

 

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perimeter is 23m
area is 17m2
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For area Split figure ( i ) into two parts

2*4 = 8m + 6*1.5 m = 9m =8+9 = 17m​2

Perimeter : 4m + 4m +1.5m + 6m + 5.5m + 2m =  23 m

For area of figure (ii) split into three parts
3*5 = 15m +2*5 = 10m + 13*2 = 26m​2

​Perimeter : 3m+ 5m+8m+5m+2m+7m+13m+7m = 50m

​For area of figure (iii) split into four parts 
5*2=10cm + 3*2=6cm + 5*2=10cm +12*2 =24cm = 50cm​2

Perimeter = 12+7+2+5+4+3+2+3+4+5+2+7 = 56cm
 
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For area Split figure ( i ) into two parts

2*4 = 8m?+ 6*1.5 m = 9m?=8+9 = 17m?2

Perimeter :?4m?+ 4m +1.5m + 6m + 5.5m + 2m?= ?23 m

For area of figure (ii) split into three parts
3*5 = 15m +2*5 = 10m + 13*2 = 26m?2

?Perimeter : 3m+ 5m+8m+5m+2m+7m+13m+7m = 50m

?For area of figure (iii) split into four parts?
5*2=10cm + 3*2=6cm + 5*2=10cm +12*2 =24cm = 50cm?2

Perimeter = 12+7+2+5+4+3+2+3+4+5+2+7 = 56cm
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