no. of electrons of sodium with n+l value 3 are....
Dear Student,
Sodium = 11 electron and shell configuration = 2,8,1 and in terms of n+1 is
n = 0 +1 = 1 and electron in shell = 2
n = 1+1 = 2 and electron in shell = 2
n = 2+1 = 3 and electron in shell = 6 & 1 = 6+1 =7
so total in n+1=3 is 7 electrons.
Regards.
Sodium = 11 electron and shell configuration = 2,8,1 and in terms of n+1 is
n = 0 +1 = 1 and electron in shell = 2
n = 1+1 = 2 and electron in shell = 2
n = 2+1 = 3 and electron in shell = 6 & 1 = 6+1 =7
so total in n+1=3 is 7 electrons.
Regards.