number of bivalents is 8 in prophase 1 .in such a case the number of chromosomes during anaphase 2 will be

Dear student

Please refer the solution below for the said query

Bivalent is a pair of synapsed homologous chromosomes. When homologous chromosomes start to pair up, they appear as bivalents. Each bivalent is formed of one paternal (father) and one maternal (mother) chromosome. 
The paternal and maternal chromosome each have two sister chromatids (one original and one duplicated) joined by centromere. 

In meiosis I, the homologous chromosomes separate but two sister chromatids (one parental strand and one newly formed strand) remain joined at centromere.

If a cell has 8 bivalents in prophase I, then at the end of meiosis I, the homologous chromosomes are separated such that each cell will receive half chromosomes (i.e 8 chromosomes here). 

Meiosis II, is equational division where parental chromosome and newly formed chromosome separate. Hence, each cell will receive 8 chromosomes again each. 

Thus, a cell with 8 bivalents will form 4 cells after meiosis I with 8 chromosomes each.

Hope this information clears your doubt about the topic.


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