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Number of lone pairs in 18ml H2O at 273K is xNA. Then value of x=

18 ml  water means-18 gm water (Density of water = 1 g/ml)
so, no. of moles of H2O=1 mol
IN one no. of LONE PAIRS =2 NA(in a water molecule O have two lone lone pairs)
so, x=2
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Number of lone pair in 18 ml H2O at 273 kelvin is
  • 2

18 ml  water means-18 gm water (Density of water = 1 g/ml)
so, no. of moles of H2O=1 mol
IN one no. of LONE PAIRS =2 NA(in a water molecule O have two lone lone pairs)
so, x=2
  • -2

18 ml  water means-18 gm water (Density of water = 1 g/ml)
so, no. of moles of H2O=1 mol
IN one no. of LONE PAIRS =2 NA(in a water molecule O have two lone lone pairs)
so, x=2   This is the answer.
  • -2
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