number of moles of KClO3 required to produce 5.6 litres of O2 at STP is-

2 KClO3 2 KCl + 3 O2Thus 2 moles of KClO3 gives 3 × 22.4 L oxygenThat is67.2 L of oxygen is produced from 2 molesSo 5.6 L of oxygen is produced from = 267.2×5.6 =0.1667 moles

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