numbers are selected at random,one at a time,from the two digit numbers 00,01,02.....99 with replacement.An Event E occurs if and only if the product of the two digits of a selected number is 18.If four numbers are selected find the probability that the event E atleast occurs 3 times
 

Dear student
Out of the numbers 00,01,02,...,99 those numbers the product of whose digits is 18 are 29,36,63,92.P(E)=4100=125PE¯=1-125=2425The probability that in selecting from numbers the event E occurs at least three times.=4C112532425+4C41254=4×24254+1254=97254
Regards

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I dont know bro
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What are you looking for?