OABCO is a quadrant of a circle of diameter 14 cm.the perimeter of the quadrant is?

Given: Diameter of quadrant of a circle = 14 cm

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radius =7cm

perimeter of quadrant = 1/4 * 2 ╥r

                                        1/2 ╥r

                                         1/2*22/7*7

                   =11cm sq.

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in the options it was not given this answer out of four!

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