if the length of 3 sides of trapezium other than base are equal to 10 cm then find areac of trapezium when it is maximum

Here is the answer to your question.

 
Consider the trapezium ABCD, where AD||BC, AB = CD = AD = 10 cm
Let BC = x
 
 
Draw AM ⊥ BC and DN⊥ BC
∴MN = 10 cm
Let BC = x cm
Let P = 16A2 = (x + 10)3 (30 – x)
More is P, more is A
Thus, area is more
 
 
Hope! This will help you.
Cheers!

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