of a group of 120 students, 90 take mathematics and 72 take economic. if 10 students take neither of two. how many take both?

Let n(A)= number of students taking mathematics=90n(B)= number of students taking economics=72n(AB)= number of students taking at least one subject=120 - 10 = 110n(AB)= number of students taking both subjects=?Now, n(AB)=nA+nB-nAB110=90+72-nAB nAB=52

  • 6
[(90+72) -10] - 120
52
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