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Olivia selects three numbers randomly from the following set of 5 numbers : 7, 8, 6, 9, 13

She puts them in the form of a_{ b/c }(a whole b by c)

Whats the probability that she will get a fraction more that 153/22?

Please find below the solution to the asked query:

Given : Olivia selects three numbers randomly from the following set of 5 numbers : 7, 8, 6, 9, 13

And She puts them in the form of $\mathrm{a}\frac{\mathrm{b}}{\mathrm{c}}$

And to find probability that she will get a fraction more that $\frac{153}{22}$ we write that fraction in mixed fraction , As :

$\frac{153}{22}=\frac{132+21}{22}=\frac{132}{22}+\frac{21}{22}=6+\frac{21}{22}=\mathbf{}\mathbf{6}\frac{\mathbf{21}}{\mathbf{22}}$

But from given numbers 7, 8, 6, 9, 13 we can form number in the form of $\mathrm{a}\frac{\mathrm{b}}{\mathrm{c}}$ is always greater than given fraction $\frac{153}{22}$

So,

**Probability that she will get a fraction more that $\frac{153}{22}$ = 1 ( Ans )**

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