OM is perpendicular to the chord AB of circle with centre O.If OA = 13cm , AB =24 cm then find the length of OM ? Share with your friends Share 0 Varun.Rawat answered this We have , a circle with centre at O and AB is a chord of the circle such that AB = 24 cmAlso, OM⊥AB.We know that a ⊥ drawn from the centre to the chord bisects the chord.So, AM = MB = AB2 = 242 = 12 cmNow, OA = 13 cmIn ∆OMA,OA2 = OM2 + AM2 Pythagoras Theorem⇒132 = OM2 + 122⇒169 = OM2 + 144⇒OM2 = 169 - 144⇒OM2 = 25⇒OM = 5 cm 2 View Full Answer
