on analysis , it was found that the black oxide of copper , red oxide of copper , litherage, the - Science - Atoms and Molecules

Question

on analysis , it was found that the black oxide of copper , red
oxide of copper , litherage, the red oxide of lead and peroxide of
lead contain 79 90%, 88 8%, 92 88%, 90 6% and 86 6% respectively of
the metal establish the law of multiple proprotions with the help
of data

Pankaj Singh · Accepted Answer

First calculate the mass of metals combined with fixed mass of
oxygen
For Black oxide of Cu
79 9 parts metal combines with 20 1 parts of O
So
1 part Oxygen will combine = 79 9/20 1 =3 9 part of metal
similarly
For red oxide
1part O will combine = 88 8/11 2 =7 9 parts metal
There is a fixed mass of O in both the oxides
Ratio of masses of Cu in both case = 3 9:7 9
The simplest ratio
1:2
Hence it establish the low of multiple proportion
Similarly you can calculate for oxides of Pb
Try yourself and in case you face any problem do get back to
us
good luck

on analysis , it was found that the black oxide of copper , red oxide of copper , litherage, the red oxide of lead and peroxide of lead contain 79.90%, 88.8%, 92.88%, 90.6% and 86.6% respectively of the metal. establish the law of multiple proprotions with the help of data