on solving the equation 3x1+2x2=15 5x1+2x2=20 how we gets point 5/2,15/2
let3 x1+2 x2=15 be equation 1
and 5 x1+2 x2=20 be equation 2
subtracting equation 1 from 2, we get
2x1=5
x1=5/2
substitute this value of x1 in equation 1, we get
3* 5/2 +2x2=15
15/2 +2x2=15
2x2=15- 15/2=15/2
x2=15/4
and 5 x1+2 x2=20 be equation 2
subtracting equation 1 from 2, we get
2x1=5
x1=5/2
substitute this value of x1 in equation 1, we get
3* 5/2 +2x2=15
15/2 +2x2=15
2x2=15- 15/2=15/2
x2=15/4