one bag contains 6 white and 5 black balls. another bag contains 5 white and 3 black balls one ball at random is transferred from first bag to the second bag. and then a ball is selected from second bag then find the probability that the ball drawn is white
answer will be 61/99.
explanation:
suppose a white ball is transferred: 6/11 and a white ball is chosen : 6/9
therefore; it gives 6/9*6/11=36/99
now, other case, black ball is transferred : 5/11
and a white ball is chosen : 5/9
therefore; it gives 5/9*5/11=25/99
net probability: 36/99 + 25/99= 61/99
Please correct me if i was wrong somewhere...
explanation:
suppose a white ball is transferred: 6/11 and a white ball is chosen : 6/9
therefore; it gives 6/9*6/11=36/99
now, other case, black ball is transferred : 5/11
and a white ball is chosen : 5/9
therefore; it gives 5/9*5/11=25/99
net probability: 36/99 + 25/99= 61/99
Please correct me if i was wrong somewhere...