One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting:
a) black and a king
b) spade or an ace
c) neither an ace nor a king
d) neither a red card nor a queen
e) other than an ace
f) a ten
g )the seven of clubs
h) the ace of spades
Below are the details of the cards:
Spades (♠) | Clubs (♣) | Diamonds (♦) | Hearts (♥) | Total Cards |
A | A | A | A | 4 |
13 | 13 | 13 | 13 | 52 |
(e) Other than an ace.
There are 4 cards of Ace in a pack, therefore remaining cards = 52 – 4 = 48
Hence there are 48 cards left other than Ace.
P(E) = (Favorable number of outcomes/ total number of outcomes).
P(E) = 48/ 52 = 12/ 13
Thus, probability of getting a card other than an Ace is 12/13.
(f) a ten
Since there are 4 cards of 10 out of 52, we get
P(E) = (Favorable number of outcomes/ total number of outcomes).
P(E) = 4/52 = 1/ 13
Thus, probability of getting a 10 is 1/13.
You can try solving the other parts by using the above distribution of the cards. If you still face any problem then do get back to us.