One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting:

a) black and a king

b) spade or an ace

c) neither an ace nor a king

d) neither a red card nor a queen

e) other than an ace

f) a ten

g )the seven of clubs

h) the ace of spades

Below are the details of the cards:

 Spades ()

 Clubs ()

  Diamonds (♦)

 Hearts ()

  Total Cards

A
2
3
4
5
6
7
8
9
10
K
Q
J

A
2
3
4
5
6
7
8
9
10
K
Q
J

A
2
3
4
5
6
7
8
9
10
K
Q
J

A
2
3
4
5
6
7
8
9
10
K
Q
J

4
4
4
4
4
4
4
4
4
4
4
4
4

13

13

13

13

52

 

 (e) Other than an ace.

There are 4 cards of Ace in a pack, therefore remaining cards = 52 – 4 = 48

Hence there are 48 cards left other than Ace.

P(E) = (Favorable number of outcomes/ total number of outcomes).

P(E) = 48/ 52 = 12/ 13

Thus, probability of getting a card other than an Ace is 12/13.

 

 

(f) a ten

Since there are 4 cards of 10 out of 52, we get

P(E) = (Favorable number of outcomes/ total number of outcomes).

P(E) = 4/52 = 1/ 13

Thus, probability of getting a 10 is 1/13.

 

You can try solving the other parts by using the above distribution of the cards. If you still face any problem then do get back to us.

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