# One gm metal M3+ was discharging by the passage of 1.81 *1023 electrons.What is the atomic weight of metal?

For discharging of metal the reaction is :
M3+ + 3e$\to$ M
Thus 1 mol of the metal is deposited by 3F = 3$×$96500 C = 289500 C

​Charge on 1.81$×$1023 electrons =  1.602$×$10-19 $×$1.81​$×$1023 C
= 2.9$×$104 C
289500  C deposit = 1 mol of metal
Thus 2.9$×$10C will deposit =  = 0.100 moles
0.100 moles =  1 g metal
Thus atomic mass of metal = 10 g/mol

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