One mole of a monoatomic gas is mixed with 3 moles of diatomic gas. Find the molecular specific heat of mixture at constant pressure? 

Dear Student,
Please find below the solution to the asked query:
 Values of Cp:For monoatomic gas: Cp1=52RTFor diatomic gas: Cp2=72RTSpecific heat at constant pressure for the mixture:Cp,mix=n1Cp1+n2Cp2n1+n2=1×52RT+3×72RT1+3=262RT4=268RT=134RT
Hope this information will clear your doubts about Specific heat.
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